G00 — Bacterial meningitis, not elsewhere classified
Is G00 billable?
No — G00 is a non-billable header code. G00 groups more specific codes and cannot be submitted on a claim. A valid ICD-10-CM code must be reported at the highest level of specificity available in its branch. Select one of the 6 billable codes beneath G00.
G00 at a glance
| Code | G00 |
|---|---|
| Description | Bacterial meningitis, not elsewhere classified |
| Billable | No — header code |
| Code set | ICD-10-CM FY2027 |
| Valid for encounters | October 1, 2026 – September 30, 2027 |
Excludes1 — never code together
The conditions below can never be reported together with G00 on the same claim. An Excludes1 note means the two conditions cannot occur in the same patient, so reporting both is a coding error.
Includes
Conditions classified to G00.
- bacterial arachnoiditis
- bacterial leptomeningitis
- bacterial meningitis
- bacterial pachymeningitis
Excludes2 — not included here — inherited from Chapter 6
The conditions below are not part of G00, but a patient may have both at the same time. When documentation supports it, G00 and the excluded code may both be reported.
- certain conditions originating in the perinatal period (P04-P96)
- certain infectious and parasitic diseases (A00-B99)
- complications of pregnancy, childbirth and the puerperium (O00-O9A)
- congenital malformations, deformations, and chromosomal abnormalities (Q00-Q99)
- endocrine, nutritional and metabolic diseases (E00-E88)
- injury, poisoning and certain other consequences of external causes (S00-T88)
- neoplasms (C00-D49)
- symptoms, signs and abnormal clinical and laboratory findings, not elsewhere classified (R00-R94)
What codes fall under G00? (6)
How long has G00 existed?
G00 has been in ICD-10-CM since at least FY2016, the earliest fiscal year on record here.
Derived from the official order files for FY2016–FY2026. FY2017 and FY2020 publish no order file, so those years are not covered.
Which codes are confused with G00?
ICD-10-CM declares these codes mutually exclusive with G00 — exactly one of each pair can be correct for a given encounter.